Question

Hey can you please help me posted picture of question

Answer 1

`4x^2-30=34\ \ \ |+30\\\\4x^2=64\ \ \ \ |:4\\\\x^2=16\to x=\pm√(16)\\\\x=\pm4\\\\\text{Answer:C. x=-4 and D. x=4}`

Answer 2

Answer:
The solutions are 4 and -4

Step-by-step explanation:
To get the solutions, we will need to isolate x on one side of the equation.
This can be done as follows:
4x² - 30 = 34
4x² - 30 + 30 = 34 + 30
4x² = 64
x² = 64/4
x² = 16
x = ±√16
either x = +√16 = 4
or x = -√16 = -4

Hope this helps :)