Question

The pyramid shown has a square base that is 14 centimeters on each side. The slant height is 15 centimeters. What is the surface area of the pyramid?

Answer 1

we know that

[surface area of the pyramid]=area of the base+4*[area of one lateral triangle]
area of the base=14*14------> 196 cm²

area of one lateral triangle=b*h/2
b is the length side of the square
b=14 cm
h is the slant height
h=15 cm
area of one lateral triangle=14*15/2-----> 105 cm²

[surface area of the pyramid]=196 cm²+4*[105 cm²]-----> 616 cm²

the answer is
616 cm²