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A 135 g sample of carbon disulfide requires 43.2 kj of heat to vaporize completely. what is the enthalpy of vaporization for carbon disulfide?

a. 1.77 kj/mol
b. 24.4 kj/mol
c. 76.2 kj/mol
d. 0.320 kj/mol
e. 3.13 kj/mol

1 Answer

2 votes
Molecular weight of CS2 = 76.14 g

number of moles of CS2 =
(weight.of.CS2)/(molecular.weight)
=
(135)/(76.14)
= 1.773

Now, 1.733 mol requires 43.2 kj of heat to vaporize.
∴ 1 mol will require
(43.2)/(1.77) = 24.4 kj/mol

Thus, correct answer is option B

answered
User Richard Haddad
by
7.9k points
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