Determine tge energy in joules of a photon whose frequency is 3.55x10

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Sunil Kumawat · Answer 1 · 2019-11-12T11:38:48+0000

E = hf
E = 6.63×10^-34 × 3.55×10 eV
1 eV = 1.60×10^-19 J
E = 6.63×10^-34 × 3.55×10 × 1.60×10^-19
E = 3.77×10^-51 J

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