Question

Three 1.2 ohm lamps are connected in series and connected to a 3 volt battery. Calculate the total current in the circuit

Answer 1

Since the 3 lamps are connected in series, their equivalent resistance is equal to the sum of the three resistors:

`R_(eq) =R_1+R_2+R_3=1.2 \Omega + 1.2 \Omega +1.2 \Omega = 3.6 \Omega`

And the total current flowing in the circuit can be calculated by using Ohm's law:

`I= (V)/(R_(eq))`
where V is the voltage of the battery. By using V=3 V, we find

`I= (3 V)/(3.6 \Omega)= 0.83 A`