Question

The height of a triangle is twice the length of its base. The area of the triangle is 50m^2. Find the height and base to the nearest tenth of a meter

Answer 1

`A = 50m^2 h = 2b`


`A = (1)/(2)bh`


`A = (1)/(2) b(2b)`


`50 = (2b^2)/(2) b^2 = 50 b = 5 √(2) = 7.1 m h = 2b = 2(5 √(2)) = 10 √(2) = 14.1 m`