Question

1. Line k is perpendicular to the graph 4x - 3y + 14 = 0 and passes through (-3,2). Find an equation in Standard

Form whose graph is line k.

Answer 1

Explanation:

any line k perpendicular to 4x-3y=14 is

3x+4y=a

∵ it passes through (-3,2)

so 3(-3)+4(2)=a

-9+8=a

a=-1

so reqd. eq. is 3x+4y=-1