Question

3.75 g of an unknown gas at 29 °C and 1.10 atm is stored in a 1.75-L flask. What is the density of the gas? What is the molar mass of the gas?

Answer 1

Answer:1.35 g/LStep-by-step explanation:1) Use PV = nRT to determine moles of gas present in gas:(1.10 atm) (2.55 L) = (n) (0.08206) (328 K)n = 0.104 mol2) Get molar mass of gas using calculated moles:0.104 mol x M g/mol = 3.45gM = 3.45 g / 0.104 mol = 33.17 g/molDensity = Molar Mass x P / RT= 33.17 g/mol x 1.10 atm / 0.0821 L mol / atm .K x 328 K= 1.35 g /LWas this helpful? plz let me know!!!!