Question

Please HELP!!! What is the sum of the geometric series - asip

Answer 1

259

Explanation:

We have the next sum

`\sum_(i=1)^(4)6^( i-1)`

Each term of the sum is

`\sum_(i=1)^(4)6^( i-1) = 6^(1-1)+6^(2-1)+6^(3-1)+6^(4-1)`

`\sum_(i=1)^(4)6^( i-1) = 6^(0)+6^(1)+6^(2)+6^(3)`

`\sum_(i=1)^(4)6^( i-1) = 1 + 6 + 36 + 216`

Finally, the result is

`\sum_(i=1)^(4)6^( i-1) = 259`

Answer 2

The sum of geometric series will be:
(6^(1-1))+(6^(2-1))+(6^(3-1))+(6^(4-1))
=6^0+6^1+6^2+6^3
=1+6+36+216
=259

Answer: 259