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A sample of neon gas occupies 0.220L at 0.860atm. What will be it’s new volume at 1.52 atm, assuming the temperature remains constant.

A sample of neon gas occupies 0.220L at 0.860atm. What will be it’s new volume at 1.52 atm, assuming the temperature remains constant.
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A sample of neon gas occupies 0.220L at 0.860atm. What will be it’s new volume at 1.52 atm, assuming the temperature remains constant.

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User LPD
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The new volume at 1.52 atm is calculated by use of Bolyes law formula

that is P1V1=P2V2
V1 = 0.220 L
P1= 0.860 atm
P2 =1.52 atm
V2=?

V2 is therefore = P1V1/P2

=(0.220 L x 0.860 atm)/ 1.52 atm= 0.1245 Liters

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User Xilef
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