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5 votes
Hey can you please help me posted picture of question

Hey can you please help me posted picture of question-example-1

2 Answers

4 votes
i believe it is b. it has one real solution
answered
User Raldi
by
8.5k points
1 vote
We have the resolvent is:
x = (- b +/- root (b2 - 4ac)) / (2a)
The discriminant is:
b2 - 4ac> 0
Therefore, the root is positive.
Thus, the equation has two real solutions.
x1 = (- b + root (b2 - 4ac)) / (2a)
x2 = (- b - root (b2 - 4ac)) / (2a)
Answer:
option C
answered
User Bootica
by
8.3k points

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