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A balloon is filled to a volume of 5.10l at a temperature of 27.1ºc. if the pressure in the balloon is measured to be 2.20 atm, how many moles of gas are contained inside the balloon?

asked
User CKKiller
by
7.9k points

2 Answers

1 vote

Final answer:

The number of moles of gas contained in the balloon is 0.121 mol.

Step-by-step explanation:

To calculate the number of moles of gas contained inside the balloon, we can use the ideal gas law equation: PV = nR

  1. P: pressure of the gas (in atm) = 2.20 atm
  2. V: volume of the gas (in L) = 5.10 L
  3. n: number of moles of gas (unknown)
  4. R: ideal gas constant = 0.0821 L·atm/mol·K
  5. T: temperature of the gas (in K) = 273.15 + 27.1 = 300.25 K

Plugging in the values into the equation, we can solve for n:
(2.20 atm)(5.10 L) = n(0.0821 L·atm/mol·K)(300.25 K)

Simplifying the equation, we find that n = 0.121 mol

answered
User Skafle
by
8.7k points
4 votes
we can find the number of moles in the balloon using the ideal gas law equation
PV = nrT
where
P - pressure - 2.20 atm
V - volume - 5.10 L
n - number of moles
r - universal gas constant - 0.08206 LatmK⁻¹mol⁻¹
T - temperature in Kelvin - 27.1 °C + 273 = 300.1 K
substituting the values in the equation
2.20 atm x 5.10 L = n x 0.08206 LatmK⁻¹mol⁻¹ x 300.1 K
n = 0.456 mol
number of moles of gas is 0.456 mol

answered
User IvanPavliuk
by
7.9k points
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