Question

What is the equation of the line shown in this graph?Enter your answer in the box.

Answer 1

y=1 we can check this by looking at the slope of the line: m=

`(1 - 1)/(2 + 4)`
so m=0. By looking at the graph we know our y-int is 1. By plugging in this information into the equation of a line we get the following: y=0x+1. That is y=1

Answer 2

y=1

Explanation:

Hello

if you have two point of a line P1,P2, you can find the slope of the line using :

`P1(x_(1),y_(1)), P2(x_(2),y_(2))`

`m=(y_(2) -y_(1) )/(x_(2) -x_(1) )`

Step 1

Let

Point 1 (-4,1)

Point 2 (2,1)

Put the values into the equation

`m=(1-1 )/(2-(-4) )\\m=(0)/(6) \\m=0`

Hint:the slope equal to zero means that the line is horizontal

Step 2

find the equation of the line using, the slope, Point 1 and the slope-point equation

`y -y_(0)=m(x-x_(0))\\y-1=0(x-(-4))\\y-1=0\\y=1\\`

the equation of the line is

y=1

Have a good day