Question

X² + 4y² = 36 The length of the minor axis is:

Answer 1

We are given

`x^2+4y^2=36`

Since, this is equation of ellipse

so, firstly we will change it into standard equation of ellipse

`((x-h)^2)/(a^2)+((y-k)^2)/(b^2)=1`

now, we can change our equation into this form

`x^2+4y^2=36`

we divide both sides by 36

we get

`(x^2)/(36)+ (4y^2)/(36) =1`

now, we can simplify it

`(x^2)/(6^2)+ (y^2)/(3^2) =1`

now, we can compare and find 'a' and 'b'

`a=6, b=3`

Since, shorter value is b

so, length of minor axis is 2b

length of minor axis is 2*3

The length of minor axis is 6...........Answer