Question

if a normal distribution has a mean of 132 and a standard devistion of 20, what is the value that has a z score of 1.8?

Answer 1

for people that have 3.6 instead of 1.8 you do the same thing,

3.6=(x-132)/20 it would be a.204 <---- apex.

Answer 2

The value would be 168.

The formula for a z-score is
z = (X-μ)/σ

Using our information, we have
1.8 = (X-132)/20

Multiply both sides by 20:
1.8(20) = ((X-132)/20)*20
36 = X-132

Add 132 to both sides:
36+132 = X-132+132
168 = X