{d}^(2) + 12d + 27

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asked Sep 11, 2019 221k views

1 Answer

Fazal Rasel · Answer 1 · 2019-09-15T12:37:29+0000

$d {}^(2) + 12d + 27$
Write 12d as a sum or difference.

$= d {}^(2) + 9d + 3d + 27$
Factor the expressions
Factor out d from the expression
Factor out 3 from the expression

= d * (d + 9) + 3(d + 9)

Factor out d + 9 from the expression.

= (d + 3) * (d + 9)

{d}^(2) + 12d + 27

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