Final answer:
To find the margin of error (e) for a confidence level of 0.95, sample size (n) of 15, and standard deviation (s) of 5.6, you can use the formula: e = Z * (s / sqrt(n)).
Step-by-step explanation:
To find the value of the margin of error (e) for a confidence level of 0.95, sample size (n) of 15, and standard deviation (s) of 5.6, you can use the formula:
e = Z * (s / sqrt(n))
Where Z is the z-score corresponding to the desired confidence level. In this case, Z = 1.96 for a 95% confidence level. Plugging in the values, we have:
e = 1.96 * (5.6 / sqrt(15)) ≈ 2.13
Therefore, the value of e, the margin of error, is approximately 2.13.