Question

What is the inverse of the given equation y=7x^2-3?

Answer 1

The inverse of this equation would be y =
`\sqrt{(x - 3)/(7) }`

Explanation:

To find the inverse of any equation, start by switching the y and x values. Then solve for the new y value. That equation will be your inverse.

y = 7x^2 - 3

x = 7y^2 - 3

x + 3 = 7y^2

`(x-3)/(7)` = y^2

`\sqrt{(x - 3)/(7) }` = y