asked 148k views
4 votes
Given DA = 14, A F = 21, KE = x, and EF = 15.

What must the value of x be in order to prove AE || KD?

Given DA = 14, A F = 21, KE = x, and EF = 15. What must the value of x be in order-example-1
asked
User Rickless
by
9.0k points

2 Answers

3 votes

Answer:


x=10

Step-by-step explanation:

We have been given an image of a triangle. We are asked to find the value of x.

We can see that triangle AFE is similar to triangle DFK. We know that corresponding sides of similar triangle are proportional, so we can set an equation to solve for x as:


(21)/(14)=(15)/(x)

Upon cross multiplying our given equation, we will get,


21x=15*14


(21x)/(21)=(15*14)/(21)


x=(15*2)/(3)


x=5*2


x=10

Therefore, the value of x is 10.

answered
User Dreadbot
by
8.1k points
5 votes

Using cross multiplication you can determine that the ANSWER is 10.

Given DA = 14, A F = 21, KE = x, and EF = 15. What must the value of x be in order-example-1
answered
User Matthew Clark
by
7.7k points
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