Find the probability of rolling a twelve first and then a three when a pair of dice is rolled twice?

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asked Sep 3, 2019 181k views

2 Answers

Darren Gourley · Answer 1 · 2019-09-09T02:21:36+0000

Total number of possible outcomes = 36

Total number of outcomes with a sum of 12 = 1
{6,6)

Total number of outcomes with a sum of 3 = 2
{1,2}{2,1}

P(12 first, then 3) = (1/36)(2/36) = 1/648

Answer: The probability is 1/648

Find the probability of rolling a twelve first and then a three when a pair of dice is rolled twice?

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