Question

An ideal gas in a sealed container has an initial volume of 2.55 l. at constant pressure, it is cooled to 18.00 °c where its final volume is 1.75 l. what was the initial temperature?

Answer 1

Data Given:
V₁ = 2.55 L

T₁ = ?

V₂ = 1.75 L

T₂ = 18 °C + 273.15 = 291.15 K

Solution:
Let suppose the Gas is acting Ideally, Then According to Charle's Law,
P₁ / T₁ = P₂ / T₂
Solving for T₁,
T₁ = V₁ × T₂ / V₂
Putting Values,
T₁ = (2.55 L × 291.15 K) ÷ 1.75 L

T₁ = 424.24 K
Or,
T₁ = 151 °C