The product of two consecutive even integers is 840 find these numbers

Question

asked Sep 13, 2019 7.2k views

1 Answer

McKabue · Answer 1 · 2019-09-18T13:10:17+0000

Integers are 2n and 2n +2
2n * (2n + 2) = 840
4n^2 + 4n -840 = 0
Solving by quadratic formula:
n = 14 and n+2 = 16
Therefore the integers (2*n and 2*n+2) are
28 and 30

check:
28 * 30 = 840

The product of two consecutive even integers is 840 find these numbers

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

No related questions found

Categories

Other Questions