asked 41.6k views
3 votes
How does the graph of f(x)=4 cos(1/2x)-3 differ from the graph of g(x)=4 cos(x)-3

asked
User Tambra
by
8.0k points

2 Answers

5 votes
The graph of f(x)=4 cos(1/2x)-3 differs from the graph of g(x)=4 cos(x)-3, f(x) is stretched horizontally.
answered
User OTStats
by
8.3k points
5 votes

Answer:

The function f(x) is stretched horizontally.

Explanation:

We are asked to determine how the graph of
f(x)=4\text{cos}((1)/(2)x)-3 differ from the graph of
g(x)=4\text{cos}(x)-3.

Let us recall transformation rules of functions.


f(ax)\rightarrow

If
a>1 function compresses horizontally.

If
a<1 function stretches horizontally.

Upon looking at function
f(x)=4\text{cos}((1)/(2)x)-3, we can see that the value of 'a' is less than 1 that is
(1)/(2)<1, therefore, the function f(x) is stretched horizontally.

answered
User Tauren
by
8.6k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.