Question

Regular triangular pyramid has 6 cm long base edge and slant height k=9 cm. Find the lateral area of the pyramid.

Answer 1

The AL equation for a Pyramid is 1/2*Pb*h
1/2*(6*3)*9
1/2*18*9
9*9
81
The AL is 81

Answer 2

The lateral area for regular pyramid is given by:
A=l√((w/2)²+h²)+w√((l/2)²+h²)
where:
w=width
l=length
h=height
plugging the values in the formula we get:
A=6√((6/2)²+9²)+6√((6/2)²+9²)
A=6√90+6√90
A=12√90
A=113.842 sq. feet
A=