What radius of a circle is required to inscribe an equilateral triangle with an area of 270.633 cm2 and an altitude of 21.65 cm? (round to nearest tenth)

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asked Dec 6, 2019 168k views

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Quasiben · Answer 1 · 2019-12-10T19:52:08+0000

Area of an equilateral triangle=(sqrt(3)/4)x^2=270.633
x^2=270.633/[sqrt(3)/4]
x^2=625
x=25
thus the length of equilateral is 25 cm
thus the radius will be given by:
r=25/sqrt(3)=14.43 cm

What radius of a circle is required to inscribe an equilateral triangle with an area of 270.633 cm2 and an altitude of 21.65 cm? (round to nearest tenth)

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