Question

A ball was kicked into the air from a balcony 20

feet above the ground, and the ball’s height above
the ground, in feet, t seconds after the ball was
kicked was ℎ() = 20 − 162 + 32. What was the
maximum height, in feet, of the ball above the
ground after it was kicked?

Answer 1

Max ht is at the vertex of the parabola, at t = -b/2a
t = -32/-32 = 1
h(1) = -16 + 32 + 20
= 36 feet
hope this helps

Answer 2

h(t) = (t) = - 16t^2 + 32t + 20
Maximum Height of parabola (vertex)
t = - b/2a
t = - 32/- 32 = 1
h (1) = - 16 + 32 + 20
Answer = 36 Feet


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