Question

What is the change in enthalpy for the combustion reaction of butane, C4H10?

2C4H10(g) + 13O2(g) → 10H2O(g) + 8CO2(g)
Given:
C4H10(g):ΔHf °= –125 kJ
H2O(g):ΔHf °= –242 kJ
CO2(g):ΔHf °= –393.5 kJ

–510.5 kJ

–5318 kJ

–54468 kJ

–5818 kJ
Done

Answer 1

the answer would be -5318KJ