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a fully inflated basketball holds .34 cubic feet of air. The basketball is overinflated to hold .64 cubic feet of air. What is the percent of changes for the volume of air inside the baskeball?

asked
User Nayana
by
8.0k points

2 Answers

5 votes

Answer:

88.2%

Explanation:

The percent of change can be calculated by finding the difference between the two volumes and then dividing by the original volume.

0.64 - 0.34 = 0.3

0.3/.34 = 0.882

This is approximately an 88.2% increase in volume.

answered
User Tom Hennen
by
8.4k points
1 vote
The percent of change can be calculated by finding the difference between the two volumes and then dividing by the original volume.

0.64 - 0.34 = 0.3

0.3/.34 = 0.882

This is approximately an 88.2% increase in volume.
answered
User J Weezy
by
7.6k points

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