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Given a≠±b and (a^2−b^2)/(a+b) =12, find a−b.

1 Answer

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\bf \cfrac{a^2-b^2}{a+b}=12\implies \cfrac{\stackrel{\textit{difference of squares}}{(a-b)\underline{(a+b)}}}{\underline{a+b}}=12\implies a-b=12
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User Artoby
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