Question

What is the solution to the equation ? sqrt 2n+28-4 sqrt n=0?

n=2
n=4
n=7
n=14

PLEASE HELP ASAP

Answer 1

Just took the test it. Is n=2

Answer 2

Hello !


`√(2n+28)-4√(n)=0\\\\√(2n+28)=4√(n)\\\\√(2n+28)^2=\left(4√(n)\right)^2\\\\2n+28=16n\\\\2n-16n=-28\\\\14n=28\\\\\boxed{\boxed{n=2}}`