Question

after a chemistry student made a AgNO3(small 3 at bottom) solution., she wanted to determine the molar concentration of it. if 22.0g of AgNO3(small 3) (molar mass=169.91 g/mol) were dissolved in water to a final solution volume of 725 mL, what is the molar concentration of this solution.

Answer 1

Molar concentration = (numbet of mol Solute)/ ( volume Solution)

1) Finding
the number of the mol solute


`22.0 g AgNO3 * (1 mol AgNO3)/(169.91 g AgNO3) = 0.129 mol AgNO3 2) 725 ml = 0.725 L`


`3) Molarity = (number/ mol/solute)/(Volume/solution) = (0.129)/(0.725)`


`Molarity= (0.178 mol)/(L) , or 0.178 M`