A softball diamond is a square 60 ft on a side. what is the length from home to second base? (using pythagorean theorem)

Question

asked Feb 1, 2019 129k views

1 Answer

← Prev Question Next Question →

Ask a Question

DaneSoul · Answer 1 · 2019-02-05T15:56:43+0000

60^2 + 60^2 = SH(or c^2) (second to home)

60^2 = 3600 +3600 = 7200

take sqrt of 7200 you get 84.85

therefor the distance from second to home is 84.85 ft

A softball diamond is a square 60 ft on a side. what is the length from home to second base? (using pythagorean theorem)

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

No related questions found

Categories

Other Questions