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1 vote
Which shows the following expression after the negative exponents have been eliminated? xy^-6/x^-4 y^2, x=/0 y=/0

2 Answers

3 votes
The expression would be
(x^5)/(y^8) after the negative exponents have been removed.

A negative exponent basically tells us to "flip" the side of the fraction it's on. This means that y⁻⁶ on the numerator would go to the denominator, and that x⁻⁴ on the denominator would go to the numerator. This gives us:


(x* x^4)/(y^2* y^6)=(x^5)/(y^8)
answered
User JuFo
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8.1k points
4 votes

It would be B, xx4 y2y6

answered
User MariaJen
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7.8k points

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