Question

Find the value of n such that x2 – 10x + n is a perfect square trinomial.

Answer 1

value of n such that x2 – 10x + n is a perfect square trinomial.
ANSWER: 25

Answer 2

In a perfect square trinomial , the terms are in the form of

`a^2 + 2ab + b^2` , so that it can be factored and we get
`(a+b)^2`

Now lets compare the given expression

`x^2 - 10x + n`

Now we can compare this with
`a^2 + 2ab + b^2`

we get a=x , 2ab = -10x

So we get

2(x) b = -10x

it means 2b = -10

b=-5

But
`n=b^2 = (-5)^2 = 25`

Hence, n= 25