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An Ellipse is centered at (0,0) if the equation of the ellipse is 14x^2+4y^2=196 find the equation of the ellipse in standard form and the vertiesOf both the major and minor axis

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14 x^(2) +4 y^(2) = 196
(14 x^(2) )/(196) + (4y)/(196) = 1

( x^(2) )/(14) + ( y^(2) )/(49) = 1 To find Major Axis we have to find biggest denominator, it is 49. The major axis is on the y-axis. 49=a^2, a=7, Center (0,0). Vertices of major axis =(0,0+a) and (0,0-a) Vertices of major axis(0,-7), (0,+7) Minor axis is on the x-axis. b^2=14, b= √(14) Vertices of minor axis (- √(14), 0), ( √(14) , 0)
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User Girish Kolari
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4 votes

Answer:

C edge2020

Explanation:

An Ellipse is centered at (0,0) if the equation of the ellipse is 14x^2+4y^2=196 find-example-1
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User Nyteshade
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