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Given the points A(-1,-3) and B(5,2). A. Write the equation of the straight line AB. Another line MN is parallel to AB and passes through the point (6,-2). B. Write the equation of the straight line MN

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Find slope of AB where A = (-1,-3) and B = (5,2):


\text {Slope = } (Y_2-Y_1)/(X_2-X_1)


\text {Slope = } (2+3)/(5+1) = (5)/(6)

Write equation with the slope found:


y = mx + b


y = (5)/(6) x + b

Find y-intercept:


y = (5)/(6) x + b


2 = (5)/(6) (5) + b


2 = (25)/(6) + b


b = 2 - (25)/(6)


b = -(13)/(6)

Form the equation:


y = (5)/(6) x - (13)/(6)


\boxed {\boxed {\bf \text {Answer: Line AB : }y = (5)/(6) x - (13)/(6)}}


Find Slope of Line MN where MN is parallel to AB:



\text {Slope of MN = Slope of AB = } (5)/(6)

Write equation with the slope found:


y = mx + b


y = (5)/(6) x + b

Find y-intercept given that the line passed through (6, -2):


y = (5)/(6) x + b


-2 = (5)/(6) (6) + b


-2 =5 + b


b = -2 - 5


b = -7


\boxed {\boxed {\bf \text {Answer: Line MN } : y = (5)/(6) x -7 }}

answered
User Tim Bird
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