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A box of 100 computer chips contains eight defective chips. suppose we selected a random sample of 10 chips from that box. find the probability that the sample had:

a. at least one defective chip
b. all defective chips
c. nine defective chips
d. no defective chips
e. find the mean f. find the variance g. find the standard deviation question 13 options: spell check

1 Answer

3 votes
N = # of chips = 100
M = # of defective chips = 8
S = sample size = 10

a) P(X ≥ 1) = 1 - [((N-M)! / (N-M-S)!) / (N! / (N-S)!)] ≈ 0.583
b) P(X = 10) = 0 (because S > M)
c) P(X = 9) = 0 (because 9 > M)
d) P(X = 0) = 1 - P(X ≥ 1) ≈ 0.417
answered
User Asad Rao
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