asked 144k views
5 votes
What is the oxidation state of an individual sulfur atom in so42−?

1 Answer

2 votes

The oxidation state of single oxygen atom is -2 since it is more electronegative and like to gain electrons.

The sum of the oxidation states of each atom = charge of compound

Let’s say the oxidation state of Sulfur is x.

Hence,

x +4 * (-2) = -2

x – 8 = -2

x = +6

The oxidation state of individual Sulfur atom is +6

answered
User Banzor
by
8.4k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.