Question

X+ 3/4 ≥ -1/3
Can I get help with this I need the work and answer.

Answer 1

Solving this inequality is similar to solving a regular equation. The only thing you need to worry about with inequalities is that when you are dividing or multiplying by a negative number, you must flip the inequality sign. You won't have to worry about that here!

You are told x + 3/4 ≥ -1/3. Isolate the x by subtracting 3/4 from both sides. To subtract fractions, find a common denominator on both fractions, subtract the numerators, put the difference over the common denominator, and simplify if needed. The common denominator between
`(3)/(4)` and
`- (1)/(3)` is 12.
1) To make the denominator of
`(3)/(4)`, 12, multiply it by 3/3 (aka 1):

`(3)/(4) * (3)/(3) = (9)/(12)`

2) To make the denominator of
`- (1)/(3)`, 12, multiply it by 4/4:

`- (1)/(3) * (4)/(4) = -(4)/(12)`

3) Subtract the fractions to find the inequality for x:

`x + (3)/(4) \geq - (1)/(3)\\ x + (9)/(12) \geq -(4)/(12)\\ x \geq -(4)/(12) - (9)/(12) \\ x \geq -(13)/(12)`

You answer is x ≥ -13/12, or if you want to make -13/12 a mixed number, x ≥
`-1 (1)/(12)`.