Question

What is the 4th term in the sequence b(n)=1(-2)^n-1

Answer 1

`b(n)=1(-2)^n-1`

When n = 4,

`b(4)=1(-2)^4-1`


`b(4)=16-1`


`b(4)=15`

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`b(n)=1(-2)^(n-1)`

When n = 4

`b(4)=1(-2)^(4-1)`


`b(4)=1(-2)^3`


`b(4)=1(-8)`


`b(4)=-8`