Question

Determine algebraically, three consecutive integers such that the sum of the first and the third is three times the second

Answer 1

x,x+1,x+2

Explanation:

x+2[x+1]+3[x+2]= -76

x+2x+2+3x+6= -76

6x+8=-76

6x=-76-8

6x= -84

x= -84/6

x= -14

hope it helps UvU