Question

What potential difference is required to cause 4.00 a to flow through a resistance of 330 ω?

Answer 1

We can solve the problem by using Ohm's law, which states that an Ohmic conductor the following relationship holds:

`\Delta V = I R`
where

`\Delta V` is the potential difference applied to the resistor
I is the current flowing through it
R is the resistance

In our problem, I=4.00 A and
`R=330 \omega`, so the potential difference is

`\Delta V = IR=(4.00 A)(330 \omega)=1320 V`