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3 votes
Calvin purchases a piece of heavy machinery for $32,300. The value of the machine depreciates at an annual rate of 8.3% . Which function of represents the value of the machine with an approximate equivalent monthly depreciation rate?

asked
User Ply
by
9.4k points

2 Answers

3 votes
32,300 / 8.3 = x , how much value it loses monthly.
x = $3891.56627
answered
User Juan Gonzales
by
8.3k points
2 votes

Calvin purchases a piece of heavy machinery for $32,300. The value of the machine depreciates at an annual rate of 8.3%

Annual depreciation rate = 8.3% =
(83)/(100) = 0.083

For monthly depreciation rate we we raise to the exponent
(1)/(12). Also we multiply the number of years by 12.

We know depreciation formula is


A = p (1 - r)^t

Where 'p' is the initial cost, 'r' is the annual depreciation rate and 't' is the number of years

Here p = 32,300

r = 0.083 for monthly we raise to the exponent
(1)/(12)

so
(1-r)(1)/(12)^

t= number for years , for monthly we put 12t

So equation becomes


A = 32300 ( (1-0.083)^(1)/(12) )^(12t)


A = 32300 ( 0.917^(1)/(12) )^(12t)

function of represents the value of the machine with an approximate equivalent monthly depreciation rate is


f(t) = 32300 ( 0.917^(1)/(12) )^(12t)

answered
User Ivan Vasiljevic
by
7.6k points

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