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Find two rational functions f(x) and g(x) such that
f(x) * g(x) = x^(2) and
(f(x))/(g(x)) = ((x-1)^2)/((x+2)^2)

asked
User Sussy
by
8.8k points

1 Answer

5 votes

\frac fg=((x-1)^2)/((x+2)^2)

\implies f=g((x-1)^2)/((x+2)^2)

\implies f^2=fg((x-1)^2)/((x+2)^2)

\implies f^2=x^2((x-1)^2)/((x+2)^2)

\implies√(f^2)=\sqrt{x^2((x-1)^2)/((x+2)^2)}

\implies|f|=\left|(x(x-1))/(x+2)\right|

Similarly, we can show that


|g|=\left|(x(x+2))/(x-1)\right|

Then from here we can solve for
f or
g by taking either to be both positive, or both negative. That is,


f(x)=(x(x-1))/(x+2),\,g(x)=(x(x+2))/(x-1)

or


f(x)=-(x(x-1))/(x+2),\,g(x)=-(x(x+2))/(x-1)

(Note that this is only true for
x\\eq1,
x\\eq-2, and
x\\eq0.)
answered
User Orkun Bekar
by
7.8k points

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