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A sample of 0.500 moles of gas is placed in a container of volume of 2.50L. What is the pressure of the gas in ATM if the gas is at 25 degrees celcius

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The pressure of gas at ATm is calculated using ideal gas equation
that is Pv =nRT
P = pressure =?
v= volume = 2.5 l
n= moles = 0.500moles
T= temperature in kelvin = 25 +273 = 298k
R= gas constant = 0.082 l.atm/k.mol

p is therefore = nRT/V
p = (0.5 mol x0.082 l.atm/k.mol x298k) /( 2.5l) = 4.89 atm
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User MonkeyBonkey
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