Question

Ninety-three percent of a town’s population own cars. If the number of cars owned is 5,208, what is the population of the town, if nobody owns more than 1 car?

PLEASE HELP, I DON'T GET THIS!! :((

Answer 1

What the problem is saying is that 93% of the town's population is 5,208. If no one owns more than one car, then each car in the town accounts for one person. So, therefore, 93% of the town = 5,208.

The total population of the town can be found by setting up a proportion.


`(5208)/(93) = (x)/(100)`

Cross-multiply:
`520800=93x`

Solve for x, the town's population:
`x=5600`

There are 5,600 people in the town.

Answer 2

Hey there :)

93% of a town's population own cars
If number of cars owned is 5,208

Population of town is?
Let p represent population of town


`(93)/(100)` of p = 5208

`(93)/(100)` × p = 5208

Divide 5208 by p in order to do cross multiplication ( easier way )

`(93)/(100)= (5208)/(p)`

Cross multiply:

93p = 5208 × 100
93p = 520800

Divide by 93 in order to find value of p

`(93p)/(93) = (520800)/(93)`
p = 5600

The total population of the town is 5600