Find the vertex of 4 {x}^(2) - 16x + 5

Question

Find the vertex of

`4 {x}^(2) - 16x + 5`

Answer 1

To find the x coordinate of the vertex,

x =
`(-b)/(2a)`

In this case, a = 4 and b = -6. Sub these values into the equation,

x =
`(-(-6))/(2(4))`
= 2

Sub x = 2 back into the original equation,


`4(2)^(2) -16(2)+5`
= -11

Therefore, your vertex is V(2, -11)

Hope this helped!