What is the vertex of 3(x - 8{)}^(2) + 6

Question

What is the vertex of

`3(x - 8{)}^(2) + 6`

Answer 1

y = 3(x-8)^2 + 6 is in the form y = a(x-h)^2 + k
match up the terms to see that
a = 3
h = 8
k = 6
So the vertex is (h,k) = (8,6)

Answer: (8,6)