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How many grams of cucl2 are required to prepare 1250. g of a 1.25% (by mass) cucl2 solution?
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How many grams of cucl2 are required to prepare 1250. g of a 1.25% (by mass) cucl2 solution?
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Mar 23, 2019
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How many grams of cucl2 are required to prepare 1250. g of a 1.25% (by mass) cucl2 solution?
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The grams of CuCl2 required to prepare 1250g of 1.25% by mass is calculated as follow
1250 = 100%
what about 1.25%
by cross multiplication
= 1.25 x1250/100 =
15.63 grams
Mayen
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Mar 28, 2019
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