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Find the 8th term of the geometric sequence if a = 3, and r = 4.

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User OlavT
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\bf n^(th)\textit{ term of a geometric sequence} \\\\ a_n=a_1\cdot r^(n-1)\qquad \begin{cases} n=n^(th)\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio}\\ ----------\\ a_1=3\\ r=4\\ n=8 \end{cases} \\\\\\ a_8=3\cdot 4^(8-1)\implies a_8=3\cdot 4^7
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User Agustin
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